document.write( "Question 296466: a company has found that the daily demand for its product varies inversely as the price of the product. when the price is $24, the demand is 1,000 units. what is the demand if the price is increased to $30? set up a variation problem and find the value of k. then solve for the demand when the price is $30 \n" ); document.write( "
Algebra.Com's Answer #213600 by stanbon(75887)\"\" \"About 
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a company has found that the daily demand for its product varies inversely as the price of the product.
\n" ); document.write( "d = k/p
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\n" ); document.write( "Find \"k\":
\n" ); document.write( "when the price is $24, the demand is 1,000 units.
\n" ); document.write( "1000 = k/24
\n" ); document.write( "k = 24000
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\n" ); document.write( "So the relation is d = 24000/p
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\n" ); document.write( "what is the demand if the price is increased to $30?
\n" ); document.write( "d = 24000/30
\n" ); document.write( "d = 800
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "\n" ); document.write( "set up a variation problem and find the value of k. then solve for the demand when the price is $30
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