document.write( "Question 296311: Among a 16 applicants for a job, 10 have college dgrees. If three of the applicants are randomly selected for interviews, what are the probabilites that :
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Algebra.Com's Answer #213562 by Edwin McCravy(20055)\"\" \"About 
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Among a 16 applicants for a job, 10 have college dgrees. If three of the applicants are randomly selected for interviews, what are the probabilites that :\r
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Exactly
one has a college degree
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document.write( "The numerator is the number of ways to chose 1 college grad and 2\r\n" );
document.write( "non-grads.  That's \"10 choose 1\" times \"6 choose 2\", or\r\n" );
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document.write( "Numerator of desired probability = \"10C1%2A6C2=10%2A15=150\"\r\n" );
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document.write( "The denominator is \"16 choose 3\" or 16C3 or 560.\r\n" );
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document.write( "So the desired probability is \"150%2F560=15%2F56\"\r\n" );
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document.write( "The number of possibilities here is the sum:\r\n" );
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document.write( "1.  the number of ways exactly 2 have college degrees (and 1 doesn't),\r\n" );
document.write( "which is \"10 choose 2\" times \"6 choose 1\"\r\n" );
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document.write( "\"10C2%2A6C1=45%2A6=270\" \r\n" );
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document.write( "plus \r\n" );
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document.write( "2.  the number of ways exactly 3 (all 3) have college degrees (and none don't), which is \"10 choose 3\", or\r\n" );
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document.write( "\"10C3+=+120\"   \r\n" );
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document.write( "So the numerator of the desired probability is this total: 270+120=390\r\n" );
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document.write( "The denominator is, as before in part i), \"16 choose 3\" or 16C3 or 560.\r\n" );
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document.write( "So the desired probability is \"390%2F560=39%2F56\"\r\n" );
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document.write( "Edwin
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