document.write( "Question 296318: A rectangular field is to be enclosed with a fence. One side of the field is against an existing fence, so that no fence is needed on that side. If material for the fence cost $2 per foot for the two ends and $4 per foot for the side parallel to the existing fence, find the dimensions of the field of the largest area that can be enclosed for 1,000.\r
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Algebra.Com's Answer #213554 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular field is to be enclosed with a fence.
\n" ); document.write( " One side of the field is against an existing fence, so that no fence is needed on that side.
\n" ); document.write( " If material for the fence cost $2 per foot for the two ends and $4 per foot for
\n" ); document.write( " the side parallel to the existing fence, find the dimensions of the field of
\n" ); document.write( " the largest area that can be enclosed for 1,000.
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\n" ); document.write( "Let L = length of the $2 sides
\n" ); document.write( "Let W = length of the $4 side
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\n" ); document.write( "2(2L) + 4W = 1000
\n" ); document.write( "4L + 4W = 1000
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "L + W = 250
\n" ); document.write( "L = (250-W)
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\n" ); document.write( "Area:
\n" ); document.write( "A = L*W
\n" ); document.write( "Replace L with (250-W)
\n" ); document.write( "A = (250-W) * W
\n" ); document.write( "A = -W^2 = 250W
\n" ); document.write( "Find the axis of symmetry: a=-1; b=250, will give max area
\n" ); document.write( "W = \"%28-250%29%2F%282%2A-1%29\"
\n" ); document.write( "W = +125 ft, length of $4 side
\n" ); document.write( "then
\n" ); document.write( "L = 250-125 = 125 ft, length of the $2 sides
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\n" ); document.write( "Max area: all three sides = 125 ft
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\n" ); document.write( "Check 2(2*125) + 4(125) = $1000
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