document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=296356>Question 296356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alice is 8 years older than her brother john. in 5 years she will be twice as old as john. how old are alice and john now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213550 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = Alice's present age and J = John's present age.<BR>\n" );
document.write( "1) A = J+8 \"Alice is 8 years older than...John.\"<BR>\n" );
document.write( "2) A+5 = 2(J+5) \"In 5 years,she will be twice as old as John.\"<BR>\n" );
document.write( "Substitute A = J+8 from equation 1) into equation 2) and solve for J.<BR>\n" );
document.write( "2a) (J+8)+5 = 2(J+5) Simplify and solve for J<BR>\n" );
document.write( "2b) J+13 = 2J+10 Subtract J from both sides.<BR>\n" );
document.write( "2c) 13 = J+10 Subtract 10 from both sides.<BR>\n" );
document.write( "2d) J = 3 and A = J+8 = 11<BR>\n" );
document.write( "Alice is 11 years old and John is 3 years old. </SPAN>\n" );
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