document.write( "Question 296264: h(t)=c-(d-4t)(d-4t)
\n" ); document.write( "At time t=0, a ball was thrown upward from an initial height of 6 feet. until the ball hit the ground, its height, in feet, after t seconds was given by the function h above, in which c and d are positive constants. if the ball reached its maximum height, of 106 ft at time t+2.5, what was the height, in feet, of the ball at time t=1.
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Algebra.Com's Answer #213525 by richwmiller(17219)\"\" \"About 
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h(t)=c-(d-4t)(d-4t)
\n" ); document.write( "t=2.5
\n" ); document.write( "h(2.5)=106
\n" ); document.write( "h(0)=6
\n" ); document.write( "6=c-(d)^2
\n" ); document.write( "106=c-(d-10)^2
\n" ); document.write( "c=106 d=10
\n" ); document.write( "h(t)=106-(10-4t)^2
\n" ); document.write( "h(1)=70
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