document.write( "Question 296244: A rectangular piece of cardboard has a total length that measures 6 inches more than its total width. A 2-inch by 2-inch square is cut out of each corner, and the remaining sides are turned up at the dotted lines and their edges taped together to make a box with no top. The volume of the box is 110 cubic inches. What were the dimensions of the original piece of cardboard? \n" ); document.write( "
Algebra.Com's Answer #213508 by Earlsdon(6294)\"\" \"About 
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If L and W are the length and width, respectively, of the original piece of cardboard, and the cut-out corners are 2X2 inches, then the volume (V) of the newly-formed open top box with a height (h) of 2 inches can be expressed as:
\n" ); document.write( "\"V+=+%28L-4%29%2A%28W-4%29%2Ah\" Substitute \"L+=+W%2B6%29\"
\n" ); document.write( "\"V+=+%28%28W%2B6%29-4%29%2A%28W-4%29%2A2\" and the volume of this box is given as \"V+=+110\"cu.in., so we can write:
\n" ); document.write( "\"110+=+%28W%2B2%29%2A%28W-4%29%2A2\" Simplify and solve for W.
\n" ); document.write( "\"110+=+2%28W%5E2-2W-8%29\" Divide both sides by 2.
\n" ); document.write( "\"55+=+W%5E2-2W-8\" Subtract 55 from both sides.
\n" ); document.write( "\"W%5E2-2W-63+=+0\" Solve by factoring.
\n" ); document.write( "\"%28W%2B7%29%28W-9%29+=+0\" so that...
\n" ); document.write( "\"W+=+-7\" or \"W+=+9\" Discard the negative solution as the width W is a positive quantity.
\n" ); document.write( "\"highlight%28W+=+9%29\"inches. and...
\n" ); document.write( "\"L+=+W%2B6\"
\n" ); document.write( "\"highlight%28L+=+15%29\"inches.
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