document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4549>Question 4549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a system of equations and solve:\r<BR>\n" );
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document.write( "Molly is 5 years younger than Heidi.  In 3 years, Heidi will be twice as old as Molly.  How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2135 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = Molly's age (smaller number) x+5 = Heidi's age. Then  x+3 = Molly's age in 3 years. (x+5)+3 = Heidi's age in three years.\r<BR>\n" );
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document.write( "x+3= (x+5)+3 Now in 3 years Heidi will be twice as old as Molly. so,<BR>\n" );
document.write( "2(x+3)=(x+5)+3<BR>\n" );
document.write( "2x+6=x+5+3<BR>\n" );
document.write( "2x-x=5+3-6<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "Thus, Molly is 2 years and Heidi 7. In three years Molly will be 5 and Heidi 10. 10 = twice Molly's age. </SPAN>\n" );
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