document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=296144>Question 296144</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok, this is my last one that I need help with tonight, again word problems are killing me.\r<BR>\n" );
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document.write( "If I invest $1000 on May 18th in a savings account that pays 10% interest compounded every month, and I invest $1000 (on the same day) in an account which pays 10% interest that is compounded continuously:\r<BR>\n" );
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document.write( "Which will be worth more in one year? \r<BR>\n" );
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document.write( "By how much?\r<BR>\n" );
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document.write( "joe </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213477 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=P(1+r/q)^nq  compounded monthly\r<BR>\n" );
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document.write( "a= 1000(1+10/12)^1*12\r<BR>\n" );
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document.write( "a=1000(12.1/12)^12\r<BR>\n" );
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document.write( "=1104.71\r<BR>\n" );
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document.write( "for continuous caculation of CI\r<BR>\n" );
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document.write( "a=p*e^rt\r<BR>\n" );
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document.write( "a=1000*e^0.1*1\r<BR>\n" );
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document.write( "=1105.17 </SPAN>\n" );
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