document.write( "Question 296126: Samuel left the house at noon heading to David's store, 60 miles away. David left his store at 2 pm, heading to Samuel's house and traveling at twice Samuel's speed. The two men met at 3 p.m. How fast was David traveling? \n" ); document.write( "
Algebra.Com's Answer #213476 by MathTherapy(10555)\"\" \"About 
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Samuel left the house at noon heading to David's store, 60 miles away. David left his store at 2 pm, heading to Samuel's house and traveling at twice Samuel's speed. The two men met at 3 p.m. How fast was David traveling?\r
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\n" ); document.write( "\n" ); document.write( "Since the journey from David's store to Samuel's house is 60 miles, then the sum of the distances traveled by the 2 will total 60, or, \r
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\n" ); document.write( "\n" ); document.write( "Samuel's distance covered + David's distance covered = 60 miles\r
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\n" ); document.write( "\n" ); document.write( "Let Samuel's speed be S, then David's speed will be 2S, since David is traveling at twice Samuel's speed\r
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\n" ); document.write( "\n" ); document.write( "Then Samuel's distance traveled = S(3), since it took him 3 hours to cover the distance to the meeting point, and\r
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\n" ); document.write( "\n" ); document.write( "David's distance covered = 2S(1), since it took David 1 hour to cover the distance to the meeting point\r
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\n" ); document.write( "\n" ); document.write( "Therefore, we'll have: 3S + 2S = 60\r
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\n" ); document.write( "\n" ); document.write( "5S = 60\r
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\n" ); document.write( "\n" ); document.write( "S = \"60%2F5+=+12\"\r
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\n" ); document.write( "\n" ); document.write( "Now, since S, or Samuel's speed is 12 mph, then David's speed = \"highlight_green%2824%29\"mph (2S, or 2*12).
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