document.write( "Question 296153: 4m^2+10m+3=0 \n" ); document.write( "
Algebra.Com's Answer #213458 by persian52(161)![]() ![]() You can put this solution on YOUR website! 4m^(2)+10m+3=0\r \n" ); document.write( "\n" ); document.write( "Use the quadratic formula to find the solutions. In this case, the values are a=4, b=10, and c=3. \n" ); document.write( "m=(-b\~(b^(2)-4ac))/(2a) where am^(2)+bm+c=0\r \n" ); document.write( "\n" ); document.write( "Substitute in the values of a=4, b=10, and c=3. \n" ); document.write( "m=(-10\~((10)^(2)-4(4)(3)))/(2(4))\r \n" ); document.write( "\n" ); document.write( "Simplify the section inside the radical. \n" ); document.write( "m=(-10\2~(13))/(2(4))\r \n" ); document.write( "\n" ); document.write( "Simplify the denominator of the quadratic formula. \n" ); document.write( "m=(-10\2~(13))/(8)\r \n" ); document.write( "\n" ); document.write( "Simplify the expression to solve for the + portion of the \. \n" ); document.write( "m=(-5+~(13))/(4)\r \n" ); document.write( "\n" ); document.write( "Simplify the expression to solve for the - portion of the \. \n" ); document.write( "m=(-5-~(13))/(4)\r \n" ); document.write( "\n" ); document.write( "The roots of the polynomial equation & 4m^(2)+10m+3=0. \n" ); document.write( "m=(-5+~(13))/(4),(-5-~(13))/(4)_m |