document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=296070>Question 296070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to help my son with polynomials and I am very confused.  Please explain to me.  A couple of the problems are these:\r<BR>\n" );
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document.write( "9x\"to the second power\" - 16     (answer my son has is:) (3x + 2)(3x - 2)\r<BR>\n" );
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document.write( "x\"to the second power\" + 14x + 49 (answer my son has is:) (x + 7)to the second power\r<BR>\n" );
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document.write( "x\"to the second power\" + 1/2x + 1/16 (answer my  son has is:) (x + 1/4) to the second power\r<BR>\n" );
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document.write( "Thank you.<BR>\n" );
document.write( "Heather Atkins </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213403 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9x^2-16     (answer my son has is:) (3x + 2)(3x - 2)<BR>\n" );
document.write( "(3x-4)(3x+4) ans.<BR>\n" );
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document.write( "x^2 + 14x + 49 (answer my son has is:) (x + 7)to the second power<BR>\n" );
document.write( "(x+7)^2 ans.<BR>\n" );
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document.write( "x^2 + 1/2x + 1/16 (answer my  son has is:) (x + 1/4) to the second power<BR>\n" );
document.write( "(x+1/4)^2 ans. </SPAN>\n" );
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