document.write( "Question 296071: Translate the problems into a pair of linear equations in two variables. Solve equations using either elimination or substitution. State your answer for the specified variable.\r
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document.write( "A plane flies 400 miles with the wind and 300 miles against the wind in the same length of time. If the speed of the wind is 22 mph, what is the speed of the plane in still air? \n" );
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Algebra.Com's Answer #213402 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "400=(R+22)T WITH THE WIND. \n" ); document.write( "400=RT+22T \n" ); document.write( "300=(R-22)T AGAINST THE WIND. \n" ); document.write( "300=RT-22T \n" ); document.write( "400=RT+22T SUBTRACT \n" ); document.write( "----------------- \n" ); document.write( "-100=-44T \n" ); document.write( "-44T=-100 \n" ); document.write( "T=-100/-44 \n" ); document.write( "T=2.27 HOURS FOR THE TRIP. \n" ); document.write( "400=(R+22)2.27 \n" ); document.write( "400=2.27R+49.94 \n" ); document.write( "2.27R=400-49.94 \n" ); document.write( "2.27R=350.06 \n" ); document.write( "R=350.06/2.27 \n" ); document.write( "R=154.21 MPH FOR THE PLANE IN STILL AIR. \n" ); document.write( "PROOF: \n" ); document.write( "300=(154.21-22)*2.27 \n" ); document.write( "300=132.21*2.27 \n" ); document.write( "300=300 \n" ); document.write( " |