document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295978>Question 295978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PROBLEM: The length of a rectangle is two feet more than twice the width. The area is 144 ft2 (squared). Find the length and width of the rectangle. \r<BR>\n" );
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document.write( "If possible, could you show me how you got it? If not, no worries....\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213399 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+2<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "144=(2W+2)W<BR>\n" );
document.write( "144=2W^2+2W<BR>\n" );
document.write( "2W^2+2W-144=0<BR>\n" );
document.write( "2(W^2+W-72)=0<BR>\n" );
document.write( "2(W-8)(W+9)=0<BR>\n" );
document.write( "W-8=0<BR>\n" );
document.write( "W=8 ANS. FOR THE WIDTH<BR>\n" );
document.write( "L=2*8+2=16+2=18 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "144=8*18<BR>\n" );
document.write( "144=144\r<BR>\n" );
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