document.write( "Question 296012: 1 A
\n" ); document.write( " + A
\n" ); document.write( " _________________\r
\n" ); document.write( "\n" ); document.write( " 2 B\r
\n" ); document.write( "\n" ); document.write( "in the correctly solved addition problem above, A and B represent digits . if A is not equal to B ,how many different digits from 0 through 9 could A represent ?\r
\n" ); document.write( "\n" ); document.write( "(A) two (B) three (C) five (D) seven (E) nine\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #213378 by Edwin McCravy(20062)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "The number \"1A\" is \"10%2BA\"\r\n" );
document.write( "The number \"2B\" is \"20%2BB\"\r\n" );
document.write( "\r\n" );
document.write( "So since \r\n" );
document.write( "\r\n" );
document.write( "\"1A\" + A = \"2B\",\r\n" );
document.write( "\r\n" );
document.write( "\"%2810%2BA%29%2BA=20%2BB\"\r\n" );
document.write( "\"10%2BA%2BA=20%2BB\"\r\n" );
document.write( "\"10%2B2A=20%2BB\"\r\n" );
document.write( "\"2A=10%2BB\"\r\n" );
document.write( "\"B=2A-10\"\r\n" );
document.write( "\"B=2%28A-5%29\"\r\n" );
document.write( "\"0%3C=B%3C=9\"\r\n" );
document.write( "\"0%3C=2%28A-5%29%3C=9\"\r\n" );
document.write( "\"0%3C=2A-10%3C=9\"\r\n" );
document.write( "Add 10 to all three sides:\r\n" );
document.write( "\"10%3C2A%3C=19\"\r\n" );
document.write( "\"5%3C=A%3C=9.5\"\r\n" );
document.write( "\"5%3C=A%3C=9\"\r\n" );
document.write( "\r\n" );
document.write( "So the different digits from 0 through 9 which A could represent are \r\n" );
document.write( "the five numbers 5,6,7,8,9 \r\n" );
document.write( "\r\n" );
document.write( "So the answer if five.\r\n" );
document.write( "\r\n" );
document.write( "If A=5, then B=2A-10 = 2(5)-10 = 10-10 = 0\r\n" );
document.write( "\r\n" );
document.write( "15\r\n" );
document.write( "+5\r\n" );
document.write( "--\r\n" );
document.write( "20\r\n" );
document.write( "\r\n" );
document.write( "If A=6, then B=2A-10 = 2(6)-10 = 12-10 = 2\r\n" );
document.write( "\r\n" );
document.write( "16\r\n" );
document.write( "+6\r\n" );
document.write( "--\r\n" );
document.write( "22\r\n" );
document.write( "\r\n" );
document.write( "If A=7, then B=2A-10 = 2(7)-10 = 14-10 = 4\r\n" );
document.write( "\r\n" );
document.write( "17\r\n" );
document.write( "+7\r\n" );
document.write( "--\r\n" );
document.write( "24\r\n" );
document.write( "\r\n" );
document.write( "If A=8, then B=2A-10 = 2(8)-10 = 16-10 = 6\r\n" );
document.write( "\r\n" );
document.write( "18\r\n" );
document.write( "+8\r\n" );
document.write( "--\r\n" );
document.write( "26\r\n" );
document.write( "\r\n" );
document.write( "If A=9, then B=2A-10 = 2(9)-10 = 18-10 = 8\r\n" );
document.write( "\r\n" );
document.write( "19\r\n" );
document.write( "+9\r\n" );
document.write( "--\r\n" );
document.write( "28\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );