document.write( "Question 295979: What is the axis of symmetry and vertex of the graph of the function.
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document.write( "y=4x^2+7 \n" );
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Algebra.Com's Answer #213345 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! y=4x^2+7 \n" ); document.write( ". \n" ); document.write( "y=4x^2+0x+7 \n" ); document.write( ". \n" ); document.write( "Axis of symmetry: \n" ); document.write( "x = -b/2a = -0/(2*4) = -0/8 = 0 \n" ); document.write( ". \n" ); document.write( "To find vertex, plug the above back into the equation and solve for y: \n" ); document.write( "y=4x^2+7 \n" ); document.write( "y=4(0)^2+7 \n" ); document.write( "y=0+7 \n" ); document.write( "y = 7 \n" ); document.write( "vertex is at (0,7) \n" ); document.write( ". \n" ); document.write( "Answers: \n" ); document.write( "axis of symmetry: \n" ); document.write( "x = 0 \n" ); document.write( "vertex: \n" ); document.write( "(0,7) \n" ); document.write( " |