document.write( "Question 295890: solve:\r
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document.write( "(x+17)(x-10)(x+4)>0\r
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document.write( "Please help with this question.....thanks \n" );
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Algebra.Com's Answer #213313 by richwmiller(17219) You can put this solution on YOUR website! -17 \n" ); document.write( "\n" ); document.write( "The roots are x=-17,10,and -4 \n" ); document.write( "What you have to find is when y>0 \n" ); document.write( "There are three sections to consider. \n" ); document.write( "a)from x=-17 to x=-4 \n" ); document.write( "b)from x=-4 to 10 \n" ); document.write( "c)and x>10 \n" ); document.write( "As it turns out b) 10>x>-4 is <0 and a and c are >0 \n" ); document.write( "How do you find out? Plug a value in for x in those three intervals and find y. \n" ); document.write( "(x+17)(x-10)(x+4)>0 \n" ); document.write( "b)Try x=5 since I said it doesn't work \n" ); document.write( "22*-5*9 you can see that is negative \n" ); document.write( "a) Try -5 \n" ); document.write( "17-5*-5-10*4-5 \n" ); document.write( "12*-15*-1 >0 \n" ); document.write( "c)Try 20 \n" ); document.write( "37*10*24>0 yes \n" ); document.write( " |