document.write( "Question 295886: x has a normal distribution with a mean of 70.0 and a standard deviation of 3.0. Find the following probabilities.\r
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document.write( "a. P(x < 67.0)\r
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document.write( "b. P(67.0 < x < 73.0)\r
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document.write( "c. P (x > 74.0) \n" );
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Algebra.Com's Answer #213287 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x has a normal distribution with a mean of 70.0 and a standard deviation of 3.0. Find the following probabilities. \n" ); document.write( "a. P(x < 67.0) \n" ); document.write( "z(67) = (67-70)/3 = -1 \n" ); document.write( "P(x < 67) = P(z < -1) = 0.1587 \n" ); document.write( "================================= \n" ); document.write( "b. P(67.0 < x < 73.0) \n" ); document.write( "z(67) = -1 \n" ); document.write( "z(73) = (73-70)/3 = 1 \n" ); document.write( "P(67 < x < 73) = P(-1 < z < 1)= 0.6827 \n" ); document.write( "================================= \n" ); document.write( "c. P (x > 74.0) \n" ); document.write( "z(74) = (74-70)/3 = 4/3 \n" ); document.write( "P(x > 74) = P(z > 4/3) = 0.0912 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================================== \n" ); document.write( " \n" ); document.write( " |