document.write( "Question 295875: John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John? \n" ); document.write( "
Algebra.Com's Answer #213285 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! John is 13 years less than 3 times as old as his son. \n" ); document.write( "Six years ago, he was 14 years more than twice as old as his son was then. \n" ); document.write( "How old is John? \n" ); document.write( "------------------------- \n" ); document.write( "Equations: \n" ); document.write( "j = 3s-13 \n" ); document.write( "(j-6) = 2(s-6)+14 \n" ); document.write( "--------------------- \n" ); document.write( "Substitute for \"j\" and solve for \"s\": \n" ); document.write( "(3s-13-6) = 2s-12+14 \n" ); document.write( "3s-19 = 2s+2 \n" ); document.write( "s = 21 (son's age now) \n" ); document.write( "--- \n" ); document.write( "Since j = 3s-13, j = 3(21)-13 = 50 (john's age now) \n" ); document.write( "=================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================================================== \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |