document.write( "Question 295875: John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John? \n" ); document.write( "
Algebra.Com's Answer #213285 by stanbon(75887)\"\" \"About 
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John is 13 years less than 3 times as old as his son.
\n" ); document.write( "Six years ago, he was 14 years more than twice as old as his son was then.
\n" ); document.write( "How old is John?
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\n" ); document.write( "Equations:
\n" ); document.write( "j = 3s-13
\n" ); document.write( "(j-6) = 2(s-6)+14
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\n" ); document.write( "Substitute for \"j\" and solve for \"s\":
\n" ); document.write( "(3s-13-6) = 2s-12+14
\n" ); document.write( "3s-19 = 2s+2
\n" ); document.write( "s = 21 (son's age now)
\n" ); document.write( "---
\n" ); document.write( "Since j = 3s-13, j = 3(21)-13 = 50 (john's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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