document.write( "Question 295822: solve for x: x=(square root of 2x+1) plus 1 \n" ); document.write( "
Algebra.Com's Answer #213270 by alicealc(293)\"\" \"About 
You can put this solution on YOUR website!
\"x+=+sqrt%282x+%2B+1%29+%2B+1\"
\n" ); document.write( "\"x+-+1+=+sqrt%282x+%2B+1%29\"
\n" ); document.write( "\"%28x+-+1%29%5E2+=+%28sqrt%282x+%2B+1%29%29%5E2\"
\n" ); document.write( "\"x%5E2+-+2x+%2B+1+=+2x+%2B+1\"
\n" ); document.write( "\"x%5E2+-+2x+%2B+1+-+2x+-+1+=+0\"
\n" ); document.write( "\"x%5E2+-+4x+=+0\"
\n" ); document.write( "\"x%2A%28x+-+4%29+=+0\"
\n" ); document.write( "x = 0 or x - 4 = 0
\n" ); document.write( "x = 0 or x = 4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "let's check the answer:
\n" ); document.write( "if x = 0 then
\n" ); document.write( "\"0+=+sqrt%282%2A0%2B1%29%2B1\"
\n" ); document.write( "\"0+=+sqrt%280%2B1%29%2B1\"
\n" ); document.write( "\"0+=+sqrt%281%29%2B1\"
\n" ); document.write( "\"0+=+1%2B1\"
\n" ); document.write( "\"0+=+2\"
\n" ); document.write( "because the left and the right side aren't match, so we won't use this answer
\n" ); document.write( "if x = 4 then
\n" ); document.write( "\"4+=+sqrt%282%2A4%2B1%29%2B1\"
\n" ); document.write( "\"4+=+sqrt%288%2B1%29%2B1\"
\n" ); document.write( "\"4+=+sqrt%289%29%2B1\"
\n" ); document.write( "\"4+=+3%2B1\"
\n" ); document.write( "\"4+=+4\"
\n" ); document.write( "the left side and the right side are match, so the answer is: x = 4\r
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