document.write( "Question 295835: Solve and check for extraneous solutions. 3sqrt(w+1)=6
\n" ); document.write( "I came up with w=35/3. I don't think that's correct and I'm not sure what I'm doing wrong
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Algebra.Com's Answer #213246 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve and check for extraneous solutions.
\n" ); document.write( "3sqrt(w+1)=6
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\n" ); document.write( "sqrt(w+1) = 2
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\n" ); document.write( "Square both sides to get:
\n" ); document.write( "w+1 = 4
\n" ); document.write( "w = 3
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\n" ); document.write( "Check the answer:
\n" ); document.write( "3sqrt(3+1) = 6
\n" ); document.write( "sqrt(4) = 2
\n" ); document.write( "2 = 2
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\n" ); document.write( "Solution: w = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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