document.write( "Question 295701: 9x+40<=15-x \n" ); document.write( "
Algebra.Com's Answer #213235 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"9x%2B40%3C=15-x\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"9x%3C=15-x-40\" Subtract \"40\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"9x%2Bx%3C=15-40\" Add \"x\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"10x%3C=15-40\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"10x%3C=-25\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=%28-25%29%2F%2810%29\" Divide both sides by \"10\" to isolate \"x\". \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C=-5%2F2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x%3C=-5%2F2\"
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