document.write( "Question 295782: Factoring a quadratic with leading coefficient greater than 1\r
\n" ); document.write( "\n" ); document.write( "3y^2+7y-6
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Algebra.Com's Answer #213208 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
It makes it a little more challenging but the method is the same.
\n" ); document.write( "\"3y%5E2%2B7y-6=%283y%2Ba%29%28y%2Bb%29\"
\n" ); document.write( "If you FOIL the right hand side you get,
\n" ); document.write( "\"%283y%2Ba%29%28y%2Bb%29=3y%5E2%2B3by%2Bay%2Bab\"
\n" ); document.write( "\"%283y%2Ba%29%28y%2Bb%29=3y%5E2%2B%283b%2Ba%29y%2Bab\"
\n" ); document.write( "So again look for factor of -6:
\n" ); document.write( "(1,-6)
\n" ); document.write( "(-1,6)
\n" ); document.write( "(2,-3)
\n" ); document.write( "(-2,3)
\n" ); document.write( "and try to solve for the y-coefficient until you hit the right one.
\n" ); document.write( "\"a=1\", \"b=-6\"
\n" ); document.write( "\"3b%2Ba=7\"
\n" ); document.write( "\"3%28-6%29%2B1=7\"
\n" ); document.write( "\"-18%2B1=7\"
\n" ); document.write( "\"-17=7\"
\n" ); document.write( "No
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\n" ); document.write( "\"a=-6\", \"b=1\"
\n" ); document.write( "\"3b%2Ba=7\"
\n" ); document.write( "\"3-6=7\"
\n" ); document.write( "\"-3=7\"
\n" ); document.write( "No
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\n" ); document.write( "\"a=-1\",\"b=6\" and \"a=6\",\"b=-1\" will give similar results.
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\n" ); document.write( "\"+a=2\", \"b=-3\"
\n" ); document.write( "\"3b%2Ba=7\"
\n" ); document.write( "\"3%28-3%29%2B2=7\"
\n" ); document.write( "\"-9%2B2=7\"
\n" ); document.write( "\"-7=7\"
\n" ); document.write( "No, but we only need to change the signs of a and b for this combination to work.
\n" ); document.write( "\"a=-2\", \"b=3\".
\n" ); document.write( "\"+3y%5E2%2B7y-6=%283y-2%29%28y%2B3%29+\"
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