document.write( "Question 295777: Andy deposited a total of $2100 in two accounts, a savings account and an investment
\n" ); document.write( "account. The savings account yields interest at an annual rate of 5%, and the investment
\n" ); document.write( "account yields interest at the annual rate of 6.5%. The total interest after one year
\n" ); document.write( "was $123. Determine how much Andy deposited in each account.
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Algebra.Com's Answer #213204 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
u need to find the 2 equations so u can solve
\n" ); document.write( "\"Andy deposited a total of $2100 in two accounts, a savings account and an investment account.\" meaning \"S%2BI=2100\" s=money in Savings account I=money in investment account
\n" ); document.write( "\"The savings account yields interest at an annual rate of 5%, and the investment
\n" ); document.write( "account yields interest at the annual rate of 6.5%. The total interest after one year was $123.\" this says that \".05S%2B.065I=123\" this is because 5% of S is .05S and 6.5% of I is .065I and the combined total interest is 123.
\n" ); document.write( "so now that we have the 2 equations we can substitute and solve
\n" ); document.write( "\"S%2BI=2100\"or \"S=2100-I\"
\n" ); document.write( "\".05S%2B.065I=123\" substitute the S
\n" ); document.write( "\".05%282100-I%29%2B.065I=123\"distribute
\n" ); document.write( "\"105-.05I%2B.065I=123\"add like terms
\n" ); document.write( "\"105%2B.015I=123\"subtract 105
\n" ); document.write( "\".015I=18\"divide by .015
\n" ); document.write( "\"highlight%28I=1200%29\"
\n" ); document.write( "input I into first equation to solve for S
\n" ); document.write( "\"S=2100-I\"
\n" ); document.write( "\"S=2100-1200\"
\n" ); document.write( "\"highlight%28S=900%29\"
\n" ); document.write( "check answer with secound equation
\n" ); document.write( "\".05%28900%29%2B.065%281200%29=123\" imput values for S and I and solve
\n" ); document.write( "\"45%2B78=123\"
\n" ); document.write( "\"123=123\"
\n" ); document.write( "CORRECT\r
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