document.write( "Question 295708: the population of a city is estimated to be at 432000 after 2 years.if population growth is 20% per annum,what is the current population \n" ); document.write( "
Algebra.Com's Answer #213134 by CharlesG2(834)\"\" \"About 
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the population of a city is estimated to be at 432000 after 2 years.if population growth is 20% per annum,what is the current population\r
\n" ); document.write( "\n" ); document.write( "current * 1.20 going forward (1.20 is 120% is 6/5)
\n" ); document.write( "current * 5/6 going backward (the reciprocal of 120%)
\n" ); document.write( "If we are going forward 2 years:
\n" ); document.write( "432000
\n" ); document.write( "432000 * 1.20 (20% growth) = 518400 (end of year 1)
\n" ); document.write( "518400 * 1.20 = 622080 (end of year 2)
\n" ); document.write( "If we are going backward 2 years:
\n" ); document.write( "432000
\n" ); document.write( "432000 * 5/6 = 360000 (1 year prior)
\n" ); document.write( "360000 * 5/6 = 300000 (2 years prior)
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