document.write( "Question 295503: Graph the rational funxtion f(x)=x^2+5x-6/x^2+2x-3. indentify the vertical and horizontal asymptotes, and any holes in the graph \n" ); document.write( "
Algebra.Com's Answer #213103 by Fombitz(32388)\"\" \"About 
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Simplify first.
\n" ); document.write( "You can factor numerator and denominator and get rid of common factors, if there are any.
\n" ); document.write( "\"x%5E2%2B5x-6=%28x%2B6%29%28x-1%29\"
\n" ); document.write( "\"x%5E2%2B2x-3=%28x%2B3%29%28x-1%29\"
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\n" ); document.write( "\"%28x%5E2%2B5x-6%29%2F%28x%5E2%2B2x-3%29=%28x%2B6%29%2F%28x%2B3%29%29\"
\n" ); document.write( "Vertical asymptotes occur when the denominator goes to zero.
\n" ); document.write( "For f(x), the denominator goes to zero when,
\n" ); document.write( "\"x=-3\"
\n" ); document.write( "To find horizontal asymptotes, divide numerator and denominator by the highest exponent x term, then take the limit.
\n" ); document.write( "\"f%28x%29=%28x%5E2%2B5x-6%29%2F%28x%5E2%2B2x-3%29\"
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\n" ); document.write( "\"f%28x%29=%281%2B5%2Fx-6%2Fx%5E2%29%2F%281%2B2%2Fx-3%2Fx%5E2%29\"
\n" ); document.write( "in the limit, the crossed out terms go to zero.
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\n" ); document.write( "So then
\n" ); document.write( "\"lim%28x-%3Einfinity%2C+f%28x%29%29=1\"
\n" ); document.write( "There is a horizontal asymptote at \"y=1\".
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\n" ); document.write( "Since there is a division by zero at \"x=-3\", the value of \"f%28-3%29\" is undefined.
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