document.write( "Question 295589: I have 9 coins in total of 85 cents. None of the coins are pennies. What do I have?
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document.write( "Please provide step by step, and no algebra if possible. My kid in 4th grade only. Thanks!!!! \n" );
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Algebra.Com's Answer #213035 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! You made an odd choice for help in coming to a website called algebra.com to ask for no algebra.\r \n" ); document.write( "\n" ); document.write( "Tell that to the teacher. S/he gave you the algebra problem. \n" ); document.write( "2 quarters=50 cents \n" ); document.write( "7 nickels=35 cents \n" ); document.write( "9 coins 85 cents \n" ); document.write( "another possibility \n" ); document.write( "8 dimes 80 \n" ); document.write( "1 nickel 5 \n" ); document.write( "9 coins 85 cents\r \n" ); document.write( "\n" ); document.write( "No algebra. Just magic. \n" ); document.write( "To do it without algebra would be trial and error. It is also called guessing. Just try numbers until you accidentally find the right combo.\r \n" ); document.write( "\n" ); document.write( "or you could go through the possibilities which is basically systematic guessing \n" ); document.write( "half dollar 50 \n" ); document.write( "now we need 8 more coins but the smallest is a nickel and 7*5=35 \n" ); document.write( "can't be a half dollar \n" ); document.write( "quarters 1 \n" ); document.write( "60 more cents \n" ); document.write( "8 more coins \n" ); document.write( "5 dimes and 2 nickels \n" ); document.write( "not enough \n" ); document.write( "can't be done with 9 coins and one quarter \n" ); document.write( "2 quarters 50 \n" ); document.write( "7 nickels we did already \n" ); document.write( "3 quarters and 6 more coins for 10 cents can't be done \n" ); document.write( "no quarters and no half dollars leaves dimes and nickels \n" ); document.write( "Did that already. \n" ); document.write( "8 dimes and 1 nickel. \n" ); document.write( " \n" ); document.write( " |