document.write( "Question 295607: 17\r
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Algebra.Com's Answer #213018 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Note: We can write 17 as $\"16%262%2F2\"$ since $\"16%262%2F2=16%2B2%2F2=16%2B1=17\"$ \r
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\n" ); document.write( "\n" ); document.write( "Using the note above, we can go from\r
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document.write( "  17\r\n" );
document.write( "-  8 1/2\r\n" );
document.write( "---------\r\n" );
document.write( "

\r
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\n" ); document.write( "\n" ); document.write( "to\r
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document.write( "  16 2/2\r\n" );
document.write( "-  8 1/2\r\n" );
document.write( "---------\r\n" );
document.write( "

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\n" ); document.write( "\n" ); document.write( "Now just subtract the common parts. So $\"16-8=8\"$ and $\"2%2F2-1%2F2=%282-1%29%2F2=1%2F2\"$ meaning that \r
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document.write( "  16 2/2\r\n" );
document.write( "-  8 1/2\r\n" );
document.write( "---------\r\n" );
document.write( "   8 1/2\r\n" );
document.write( "

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\n" ); document.write( "\n" ); document.write( "So this also means that \r
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document.write( "  17\r\n" );
document.write( "-  8 1/2\r\n" );
document.write( "---------\r\n" );
document.write( "   8 1/2\r\n" );
document.write( "

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