document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295595>Question 295595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot do this im stuck...\r<BR>\n" );
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document.write( "Cashews sell for $8 a pound,and peanuts for $3 a pound. A store wants to make 20 pounds of mixed nuts which they will sell for $6 a pound. How many pounds of cashews and how many pounds of peanuts should they use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #213009 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=213009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the quantity of cashews added be x\r<BR>\n" );
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document.write( "the quantity of peanuts to be added will be 20-x\r<BR>\n" );
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document.write( "the value of each added = the value of total\r<BR>\n" );
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document.write( "3*(20-x)+8x=20*6\r<BR>\n" );
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document.write( "60-3x+8x=120\r<BR>\n" );
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document.write( "5x=60\r<BR>\n" );
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document.write( "x=12 lbs cashews\r<BR>\n" );
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document.write( "y=8 lbs peanuts<BR>\n" );
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