document.write( "Question 295590: find two consecutive negative integers whose product is 132 \n" ); document.write( "
Algebra.Com's Answer #213006 by mananth(16946)\"\" \"About 
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let one integer be x\r
\n" ); document.write( "\n" ); document.write( "the other integer will be x+1\r
\n" ); document.write( "\n" ); document.write( "x(x+1)=132\r
\n" ); document.write( "\n" ); document.write( "x^2 +x-132=0\r
\n" ); document.write( "\n" ); document.write( "x^2+12x-11x-132=0\r
\n" ); document.write( "\n" ); document.write( "X(X+12)-11(X+12)=0\r
\n" ); document.write( "\n" ); document.write( "(X-11)(X+12)=0\r
\n" ); document.write( "\n" ); document.write( "X=11 OR -12\r
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\n" ); document.write( "\n" ); document.write( "SINCE THE NUMBERS ARE NEGATIVE THE NUMBERS ARE -12 & -11\r
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