document.write( "Question 295583: the perimeter of a rectangle given that the length is x yards and the width is 10 yards shorter \n" ); document.write( "
Algebra.Com's Answer #213004 by Deina(147)\"\" \"About 
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Ok,
\n" ); document.write( "Length = x
\n" ); document.write( "Width = x - 10\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2(L + W)

\n" ); document.write( "We substitute \"x\" for length, and \"x - 10\" for width:
\n" ); document.write( "Perimeter = 2(x + (x - 10))

\n" ); document.write( "Now distribute:
\n" ); document.write( "Perimeter = 2x + 2x - 20 Combine like terms:
\n" ); document.write( "Perimeter = 4x - 20 & bob's your uncle!
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