document.write( "Question 295583: the perimeter of a rectangle given that the length is x yards and the width is 10 yards shorter \n" ); document.write( "
Algebra.Com's Answer #213004 by Deina(147)![]() ![]() You can put this solution on YOUR website! Ok, \n" ); document.write( "Length = x \n" ); document.write( "Width = x - 10\r \n" ); document.write( "\n" ); document.write( "Perimeter = 2(L + W) \n" ); document.write( "We substitute \"x\" for length, and \"x - 10\" for width: \n" ); document.write( "Perimeter = 2(x + (x - 10)) \n" ); document.write( "Now distribute: \n" ); document.write( "Perimeter = 2x + 2x - 20 Combine like terms: \n" ); document.write( "Perimeter = 4x - 20 & bob's your uncle! \n" ); document.write( " |