document.write( "Question 295511: Solving Exponential Equations Using Logarithms?
\n" ); document.write( "2^x = 30\r
\n" ); document.write( "\n" ); document.write( "5^x - 1 = 3^x\r
\n" ); document.write( "\n" ); document.write( "3.53^(x+1) = 65.4\r
\n" ); document.write( "\n" ); document.write( "16^(x - 4) = 3^(3 - x)\r
\n" ); document.write( "\n" ); document.write( "7^(x - 2) = 5^x
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Algebra.Com's Answer #212997 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
2^x = 30
\n" ); document.write( "log[2](2^x)=log[2](30)
\n" ); document.write( "x=4.90689...
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\n" ); document.write( "Ed
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