document.write( "Question 295511: Solving Exponential Equations Using Logarithms?
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document.write( "2^x = 30\r
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document.write( "5^x - 1 = 3^x\r
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document.write( "3.53^(x+1) = 65.4\r
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document.write( "16^(x - 4) = 3^(3 - x)\r
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document.write( "7^(x - 2) = 5^x \n" );
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Algebra.Com's Answer #212997 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 2^x = 30 \n" ); document.write( "log[2](2^x)=log[2](30) \n" ); document.write( "x=4.90689... \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |