document.write( "Question 295499: Fred is 3 years older than George. In 4 years from now, Fred will be three times as old as George was 5 years ago. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #212948 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! Fred's age = f \n" ); document.write( "George's age = g \n" ); document.write( "f = g + 3 \n" ); document.write( "4 years from now Fred will be three times as old as George was 5 years ago: \n" ); document.write( "f + 4 = 3 * (g - 5) \n" ); document.write( "f + 4 = 3g - 15 \n" ); document.write( "g + 3 + 4 = 3g - 15 \n" ); document.write( "g + 7 = 3g - 15 \n" ); document.write( "7 + 15 = 3g - g \n" ); document.write( "22 = 2g \n" ); document.write( "22/2 = g \n" ); document.write( "11 = g \n" ); document.write( "f = g + 3 = 11 + 3 = 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, Fred is 14 years old and George is 11 years old now \n" ); document.write( " |