document.write( "Question 295366: Bob is one third the age of his father. In 12 years he will be half the age of his father. How old is each now?
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Algebra.Com's Answer #212946 by ankor@dixie-net.com(22740)\"\" \"About 
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Bob is one third the age of his father.
\n" ); document.write( "b = \"1%2F3\"f
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\n" ); document.write( "f = 3b
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\n" ); document.write( "In 12 years he will be half the age of his father.
\n" ); document.write( "(b+12) = .5(f+12)
\n" ); document.write( "b + 12 = .5f + 6
\n" ); document.write( "b = .5f + 6 - 12
\n" ); document.write( "b = .5f - 6
\n" ); document.write( "Replace f with 3b
\n" ); document.write( "b = .5(3b) - 6
\n" ); document.write( "b = 1.5b - 6
\n" ); document.write( "b - 1.5b = - 6
\n" ); document.write( "-.5b = -6
\n" ); document.write( "Multiply both sides by -2
\n" ); document.write( "b = 12 yrs is Bob's age
\n" ); document.write( "then
\n" ); document.write( "f = 3(12)
\n" ); document.write( "f = 36 is Father's age
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"In 12 years he will be half the age of his father.\"
\n" ); document.write( "12 + 12 = .5(36 + 12)\r
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