document.write( "Question 34984: how do you solve 3a+7 < 16
\n" ); document.write( "how do you solve 16 < 3q+4
\n" ); document.write( "how do you solve 20-3s > 7s
\n" ); document.write( "how do you solve 3x > -9
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Algebra.Com's Answer #21293 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
I'll do numbers 1 and 3 then you can use these as a guide to solve the others!\r
\n" ); document.write( "\n" ); document.write( "1)
\n" ); document.write( "\"3a%2B7%3C16\" Subtract 7 from both sides of the inequality.
\n" ); document.write( "\"3a%3C9\" Divide both sides by 3.
\n" ); document.write( "\"a%3C3\"\r
\n" ); document.write( "\n" ); document.write( "3)
\n" ); document.write( "\"20-3s%3E7s\" Add 3s to both sides of the inequality.
\n" ); document.write( "\"20%3E10s\" Divide both sides by 10.
\n" ); document.write( "\"2%3Es\" or\"s%3C2\"
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