document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295429>Question 295429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A businessman has three times as much money invested at 3% as he does at 4.5%. The income from both investments for a year is $675. How much is invested at each rate.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212898 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A businessman has three times as much money invested at 3% as he does at 4.5%. The income from both investments for a year is $675. How much is invested at each rate.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "Quantity: x = 3y<BR>\n" );
document.write( "Interest:0.03x + 0.045y = 675<BR>\n" );
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document.write( "Substitute for \"x\":<BR>\n" );
document.write( "0.03(3y) + 0.045y = 675<BR>\n" );
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document.write( "Multiply thru by 1000:<BR>\n" );
document.write( "3(30y) + 45y = 675000<BR>\n" );
document.write( "135y = 675000<BR>\n" );
document.write( "y = $5000.00<BR>\n" );
document.write( "x = (1/3)(5000) = $1666.67<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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