document.write( "Question 295420: solve to find x.
\n" ); document.write( "16(x-1/x-8)^2+8(x-1/x-8)+1=0
\n" ); document.write( "u=(x-1)/(x-8)
\n" ); document.write( "16u^2+8u+1=0
\n" ); document.write( "(4u+1)(4u+1)
\n" ); document.write( "4u+1=0
\n" ); document.write( "u=1/4
\n" ); document.write( "(x-1/x-8)=1/4
\n" ); document.write( "what is the next step? \n" ); document.write( "
Algebra.Com's Answer #212894 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Your continuation:
\n" ); document.write( "4u+1=0
\n" ); document.write( "4u=-1
\n" ); document.write( "u=-1/4 not 1/4
\n" ); document.write( "u=(x-1)/(x-8)\r
\n" ); document.write( "\n" ); document.write( "-1/4=(x-1)/(x-8)
\n" ); document.write( "-1*(x-8)=4*(x-1)
\n" ); document.write( "-x*8=4x-4
\n" ); document.write( "12=5x
\n" ); document.write( "12/5=x\r
\n" ); document.write( "\n" ); document.write( "or from the beginning
\n" ); document.write( "16((x-1)/(x-8))^2+8*((x-1)/(x-8))+1=0
\n" ); document.write( "multiply the second term by (x-8)/(x-8)
\n" ); document.write( "and 1 by (x-8)^2)/(x-8)^2)
\n" ); document.write( "16((x-1)/(x-8))^2+8*((x-1)(x-8)/(x-8)^2)+(x-8)^2)/(x-8)^2)=0
\n" ); document.write( "which reduces to
\n" ); document.write( "(5x-12)^2/(x-8)^2 = 0
\n" ); document.write( "and then to
\n" ); document.write( "(5 x-12)^2 = 0
\n" ); document.write( "then
\n" ); document.write( "5x-12 = 0
\n" ); document.write( "then 5x=12
\n" ); document.write( "x=12/5\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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