Algebra.Com's Answer #212887 by Edwin McCravy(20056)  You can put this solution on YOUR website! Exactly 100 people live in a village. The oldest person in the village was born in 1900 and everybody in the village was born in a different year but all on January 1st. In 1999, the sum of the digits in Julie's birth year was equal to her age. How old was she? \n" );
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document.write( "Suppose Julie's was born in the year \"19tu\", then the last \n" );
document.write( "two digits of her birth year is 10t+u, and her age in \n" );
document.write( "1999 was therefore . \n" );
document.write( "The sum of the digits of her birth year is  \n" );
document.write( "Since her age = the sum of the digits of her birth year, then \n" );
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document.write( "The least coefficient in absolute value is 2, so \n" );
document.write( "we write all other integers in that equation in terms of \n" );
document.write( "their nearest multiple of 2: \n" );
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document.write( "We divide through by 2: \n" );
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document.write( "Isolate the fractions on the right: \n" );
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document.write( "Since the left side is an integer, the right side is too. \n" );
document.write( "Let that integer be A. So both sides = A: \n" );
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document.write( "Clear the first equation of fractions: \n" );
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document.write( "Substituting in \n" );
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document.write( "u is a digit, so \n" );
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document.write( "Substituting for u \n" );
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document.write( "Since A is an integer it can only be 3, \n" );
document.write( "for 3 is the only integer in that interval. \n" );
document.write( "So  \n" );
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document.write( "Therefore she was born in 1976 and therefore in 1999, she was 23, \n" );
document.write( "and indeed the sum of the digits of her birth year is 1+9+7+6=23, \n" );
document.write( "which is her age. \n" );
document.write( "Edwin \n" );
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