document.write( "Question 295319: A metallurgist has one alloy containing 40% aluminum and another contained 57% aluminum. How many pounds of each alloy must he use to make 54 pounds containing 51% aluminum. \n" ); document.write( "
Algebra.Com's Answer #212868 by Fombitz(32388)\"\" \"About 
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Let A be the number of pounds of 40% aluminum, B be the number of pounds of 57% aluminum.
\n" ); document.write( "1.\"A%2BB=54\"
\n" ); document.write( "2.\"40A%2B57%2AB=51%2854%29=2754\"
\n" ); document.write( "Use eq. 1,
\n" ); document.write( "\"A%2BB=54\"
\n" ); document.write( "\"A=54-B\"
\n" ); document.write( "Substitue into eq. 2,
\n" ); document.write( "\"40%2854-B%29%2B57B=2754\"
\n" ); document.write( "\"2160-40B%2B57B=2754\"
\n" ); document.write( "\"17B=594\"
\n" ); document.write( "\"B=594%2F17\"
\n" ); document.write( "Then from eq.1,
\n" ); document.write( "\"A=54-B=54-594%2F17\"
\n" ); document.write( "\"A=918%2F17-594%2F17\"
\n" ); document.write( "\"A=324%2F17\"
\n" ); document.write( ".
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\n" ); document.write( "Use \"324%2F17\"(or about \"19.1\" lbs) of 40% alloy and \"594%2F17\"(or about \"34.9\" lbs) of 57% alloy to get \"54\" lbs of 51% aluminum.
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