document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295353>Question 295353</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trains a and b are traveling in the same direction on parallet tracks.  train a is traveling at 100 miles per hour and train b is traveling at 104 miles per hour.  Train a passes a station at 4:20 a.m.  If train b passes the same station at 4:50 a.m., at what time will train b catch up to train a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212859 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> train is 30 minutes ahead of train b<BR>\n" );
document.write( "In half an hour train a goes 50 miles.\r<BR>\n" );
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document.write( "Train b is gaining on train a by 4 mph . It will take 50/4 hours to catch up.<BR>\n" );
document.write( "50/4= 25/2=12.5 hours to catch up.<BR>\n" );
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