document.write( "Question 295350: We need to find the verticle and horizontal asymptote of this:\r
\n" ); document.write( "\n" ); document.write( "y=((3x-6)/(2x^2 + 6x - 80)) \n" ); document.write( "
Algebra.Com's Answer #212855 by stanbon(75887)\"\" \"About 
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We need to find the verticle and horizontal asymptote of this:
\n" ); document.write( "y=((3x-6)/(2x^2 + 6x - 80))
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\n" ); document.write( "Horizontal?
\n" ); document.write( "Procedure:
\n" ); document.write( "Find the term with the highest power of the variable.
\n" ); document.write( "That is 2x^2 in the denominator
\n" ); document.write( "and 0x^2 in the numerator.
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\n" ); document.write( "Then y = 0x^2/2x^2 = 0/2 = 0 is the horizontal asymptote.
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\n" ); document.write( "Vertical asymptote?
\n" ); document.write( "Procedure:
\n" ); document.write( "Factor the denominator:
\n" ); document.write( "2(x^2+3x - 40)
\n" ); document.write( "2(x^2+8x-5x-40)
\n" ); document.write( "2(x(x+8)-5(x+8))
\n" ); document.write( "= 2(x+8)(x-5)
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\n" ); document.write( "Solve 2(x+8)(x-5) = 0
\n" ); document.write( "x = -8 or x = 5
\n" ); document.write( "---
\n" ); document.write( "You have vertical asymptotes at x = -8 and at x = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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