document.write( "Question 295315: log(3x-3)=log(x+1)+log4 Solve\r
\n" ); document.write( "\n" ); document.write( "Do I re-write as log(3x-3)-log(x+1)=log4 to start?
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Algebra.Com's Answer #212849 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
There is an easier method available.
\n" ); document.write( "\"log%28%283x-3%29%29=log%28%28x%2B1%29%29%2Blog%28%284%29%29\"
\n" ); document.write( " \"log%28%283x-3%29%29=log%28%284%28x%2B1%29%29%29\"
\n" ); document.write( " \"3x-3=4%28x%2B1%29\"
\n" ); document.write( " \"3x-3=4x%2B4\"
\n" ); document.write( "\"-x=7\"
\n" ); document.write( "\"x=-7\"
\n" ); document.write( "However, since the log function only takes positive arguments,
\n" ); document.write( "\"3x-3%3E0\"
\n" ); document.write( "\"3x%3E3\"
\n" ); document.write( "\"x%3E1\"
\n" ); document.write( "The solution must be greater than 1.
\n" ); document.write( "No solution.
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