document.write( "Question 295225: John is 13 years less than 3 times as old as his son. Six years ago, he was 14 years more than twice as old as his son was then. How old is John? \n" ); document.write( "
Algebra.Com's Answer #212824 by conor.williams(1)![]() ![]() ![]() You can put this solution on YOUR website! j + 13 = 3s \n" ); document.write( "(j-6) - 14 = 2s \n" ); document.write( "------------------------------ \n" ); document.write( "j = 3s - 13 \n" ); document.write( "j = (2s + 14) + 6 \n" ); document.write( "------------------------------ \n" ); document.write( "3s - 13 = 2s + 20 \n" ); document.write( "s = 33 \n" ); document.write( "------------------------------ \n" ); document.write( "j = 99 - 13 \n" ); document.write( "j = 86 \n" ); document.write( "------------------------------ \n" ); document.write( "so john is 86 and his son is 33 \n" ); document.write( " |