document.write( "Question 295270: how to express the following as a single log?\r
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document.write( "1. log7+ log4- log2=\r
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document.write( "2. 2log(ab)- 3log a+ 2=\r
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document.write( "3. log (X2 - 1) - LOG (X+1) \n" );
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Algebra.Com's Answer #212815 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Remember: \n" ); document.write( "log a - log b = log a/b \n" ); document.write( "log a + log b = log ab \n" ); document.write( "alogb = log b^a \n" ); document.write( ". \n" ); document.write( "1. log7+ log4- log2= \n" ); document.write( "log(7*4) - log 2 \n" ); document.write( "log 28 - log 2 \n" ); document.write( "log 28/2 \n" ); document.write( "log 14 \n" ); document.write( ". \n" ); document.write( "2. 2log(ab)- 3log a+ 2= \n" ); document.write( "log (ab)^2 - log a^3 + 2 \n" ); document.write( "log (a^2b^2) - log a^3 + 2 \n" ); document.write( "log (a^2b^2)/a^3 + 2 \n" ); document.write( "log (b^2/a) + 2 \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "3. log (X2 - 1) - LOG (X+1) \n" ); document.write( "log (x^2-1)/(x+1) \n" ); document.write( "factoring the numerator: \n" ); document.write( "log (x-1)(x+1)/(x+1) \n" ); document.write( "log (x-1) \n" ); document.write( " \n" ); document.write( " |