document.write( "Question 295232: 5 years ago, bob was 2/3 mary's age. In 10 years, he will be 5/6 her age. How old is bob now?
\n" ); document.write( "a. 10 b. 15 c. 20 d. 21\r
\n" ); document.write( "\n" ); document.write( "How is this set up and how is it solved?
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Algebra.Com's Answer #212803 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
I'll give you the basics and let's see how you do.
\n" ); document.write( "Bob is age b now
\n" ); document.write( "Mary is age m now
\n" ); document.write( "5 years ago Bob was b-5 and Mary was m-5
\n" ); document.write( "In ten years Bob will be b+10 and Mary will be m+10
\n" ); document.write( "The biggest mistake that students make is forgetting to keep the ages balanced by adding or subtracting the same number form both.
\n" ); document.write( "I'll set up the first equation
\n" ); document.write( "5 years ago, bob was 2/3 mary's age
\n" ); document.write( "(b-5)=2/3*(m-5)
\n" ); document.write( "Now you set up the second equation.
\n" ); document.write( "In 10 years, he will be 5/6 her age\r
\n" ); document.write( "\n" ); document.write( "(b-5)=2/3*(m-5)\r
\n" ); document.write( "\n" ); document.write( "When you write the other equation, remember, they are asking for bob's age not mary's so solve for b
\n" ); document.write( "bob will be the younger because he is 2/3 of her age at one point and later 5/6 of her age.\r
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