document.write( "Question 295219: How many minutes will a car traveling at 52 miles per hour take to catch up with a car traveling at 42 miles per hour if the slower car started two hours before the faster car? \n" ); document.write( "
Algebra.Com's Answer #212795 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
This is a two part question.
\n" ); document.write( "first you can find the distance traveled by the car in 2 hours
\n" ); document.write( "second how long will it take the second car to catch it.
\n" ); document.write( "Or we can put it all in two equations and solve simultaneously.
\n" ); document.write( "Let's do both and compare.
\n" ); document.write( "in 2 hours the slow car can go 2*42=84 miles.
\n" ); document.write( "the faster car will gain on the slow car at 52-42 =10 miles an hour.
\n" ); document.write( "so it will take the faster car 84/10 =8.4 hours to catch up.\r
\n" ); document.write( "\n" ); document.write( "the faster car goes x hours at 52 mph
\n" ); document.write( "the slower car goes (x+2) hours at 42 mph
\n" ); document.write( "they will go the same distance so we set them equal
\n" ); document.write( "42(x+2)=52x
\n" ); document.write( "42x+84=52x
\n" ); document.write( "84=10x
\n" ); document.write( "84/10=x
\n" ); document.write( "8.4 hours = x
\n" ); document.write( "same results
\n" ); document.write( "but now you see why and how the equation works.
\n" ); document.write( " \n" ); document.write( "
\n" );