document.write( "Question 295209: I am struggling with some of these problems please help\r
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document.write( "Solve each system by substitution:\r
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document.write( "(b) y = 13x + 14
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document.write( " x = y - 1\r
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document.write( "John \n" );
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Algebra.Com's Answer #212776 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve each system by substitution: \n" ); document.write( "(a) 5x + y = 10 \n" ); document.write( "3x – 3y = 6 \n" ); document.write( "--------------- \n" ); document.write( "1st: Solve the 1st equation for \"y\": \n" ); document.write( "y = 10-5x \n" ); document.write( "2nd: \n" ); document.write( "Substitute for \"y\" in the 2nd equation and solve for \"x\": \n" ); document.write( "3x - 3(10-5x) = 6 \n" ); document.write( "3x -30+15x = 6 \n" ); document.write( "18x = 36 \n" ); document.write( "x = 2 \n" ); document.write( "---- \n" ); document.write( "3rd: Since y = 10-5x, solve for \"y\": \n" ); document.write( "y = 10-5*2 = 0 \n" ); document.write( "------ \n" ); document.write( "Solution: (2,0) \n" ); document.write( "Check your answer in the two original equations. \n" ); document.write( "======================================================= \n" ); document.write( "(b) y = 13x + 14 \n" ); document.write( "x = y - 1 \n" ); document.write( "---------------- \n" ); document.write( "1st: The 2nd equation is already solved for x, \n" ); document.write( "so substitute for \"x\" in the 1st equation: \n" ); document.write( "--- \n" ); document.write( "y = 13(y-1) + 14 \n" ); document.write( "y = 13y-13+14 \n" ); document.write( "y = 13y +1 \n" ); document.write( "12y = -1 \n" ); document.write( "y = -1/12 \n" ); document.write( "--- \n" ); document.write( "2nd: Since x = y-1 \n" ); document.write( "x = (-1/12)-1 \n" ); document.write( "x = -13/12 \n" ); document.write( "------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |