document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295189>Question 295189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary. the measure of one angle is twice as large as the measure of the other. find the number of degrees in each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212764 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let 1st angle = x<BR>\n" );
document.write( "so the 2nd angle = 180 - x (because they are supplementary)<BR>\n" );
document.write( "1st angle = 2 times of 2nd angle<BR>\n" );
document.write( "x = 2(180 - x)<BR>\n" );
document.write( "x = 360 - 2x<BR>\n" );
document.write( "x + 2x = 360<BR>\n" );
document.write( "3x = 360<BR>\n" );
document.write( "x = 360/3<BR>\n" );
document.write( "x = 120\r<BR>\n" );
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document.write( "so, the 1st angle = x = 120 degrees<BR>\n" );
document.write( "and the 2nd angle = 180 - x = 180 - 120 = 60 degrees </SPAN>\n" );
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