document.write( "Question 295163: The height if this over-sized container is 3 m. Its diameter is 2 m. What is its area? \n" ); document.write( "
Algebra.Com's Answer #212757 by Theo(13342)\"\" \"About 
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The container is a cylindrical solid.\r
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\n" ); document.write( "\n" ); document.write( "Don't know why you call it over-sized but that might not make a difference.\r
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\n" ); document.write( "\n" ); document.write( "It's diameter is 2 meters.\r
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\n" ); document.write( "\n" ); document.write( "It's height is 3 meters.\r
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\n" ); document.write( "\n" ); document.write( "It's radius is 1 meter which is one half the diameter.\r
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\n" ); document.write( "\n" ); document.write( "The area of its base is presumed to be a circle which would be equal to \"pi%2Ar%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Substitute 1 for r to get Area of the Base = \"pi\".\r
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\n" ); document.write( "\n" ); document.write( "Since \"pi\" = 3.141592654, then the Area of the Base = 3.141592654 square meters.\r
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\n" ); document.write( "\n" ); document.write( "The volume of the container would be equal to the Area of the Base Times the Height, which would then be equal to:\r
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\n" ); document.write( "\n" ); document.write( "3.141592654 * 3 = 9.424777961 cubic meters.\r
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\n" ); document.write( "\n" ); document.write( "The formula for the volume of the container is \"pi%2Ar%5E2%2Ah\".\r
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\n" ); document.write( "\n" ); document.write( "Since \"pi%2Ar%5E2\" is the formula for the area of the base, then the formula for the volume of the container becomes:\r
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\n" ); document.write( "\n" ); document.write( "Area of the Base * Height.\r
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