document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295121>Question 295121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If - 1/3x + 7 = 16, what is the value of 2x + 1? And how do you get that answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212736 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is it<BR>\n" );
document.write( "- 1/3*x+7=16<BR>\n" );
document.write( "or <BR>\n" );
document.write( "1/3*x+7=16<BR>\n" );
document.write( "first solve for x <BR>\n" );
document.write( "then plug the new value in 2x+1<BR>\n" );
document.write( " </SPAN>\n" );
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