document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=295068>Question 295068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> *Directions: A triangle has legs of lengths \"a\" and \"b\" and hypotenuse of length \"c\". Find the perimeter. Round to the nearest tenth, if necessary.\r<BR>\n" );
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document.write( "Problem: a=5cm, c=13cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #212697 by </B><A HREF=/tutors/aboutme.mpl?userid=ozybloke><B>ozybloke(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ozybloke><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ozybloke><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=212697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup><BR>\n" );
document.write( "13<sup>2</sup> = 5<sup>2</sup> + b<sup>2</sup><BR>\n" );
document.write( "169 = 25 + b<sup>2</sup> [subtract 25 from both sides]<BR>\n" );
document.write( "144 = b<sup>2</sup><BR>\n" );
document.write( "12cm = b \r<BR>\n" );
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document.write( "The perimeter is 5 + 12 + 13 = 30cm </SPAN>\n" );
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